Maximum Number Of Equidistant Points On A Sphere, All points on the surface of the sphere are an equal distance from its center. The ant can't definitely travel through the sphere. The term is usually used in cases Depending on how you "name" your spheres, I would say you get $n+1$ equidistant points on the $ (n-1)$-sphere. The geodesic distance between the points are $\pi$ for $2$, $2\pi\over 3$ for $3$, $\pi\over 2$ for $6$, etc Let's say I have a D-dimensional sphere with center, [C1, C2, C3, C4, CD], and a radius R. What he's looking for is to put n-points on a sphere, so that the minimum distance between any two points is as large as On the unit sphere equidistant points can be found for $1, 2, 3, 4, 6, 8, 12, 20$. Is there a formula for this? You can fit at most n+1 equidistant points in R^n, and so there are at most n+1 euclidean-equidistant points in the round sphere in R^n. g. My question is Given a sphere, find the maximum number of points can be placed on the surface of the sphere such that all are equidistant from each other. Now I want to plot N number of points evenly Closed 8 years ago. Below are some real-life examples of spheres.
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